Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 20 - Electric Circuits - Problems - Page 573: 23

Answer

$6.0\times10^{2}\,W$

Work Step by Step

Using the equation for power, we find: $P=\frac{V^{2}}{R}=\frac{(120\,V)^{2}}{24\,\Omega}=6.0\times10^{2}\,W$
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