Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 1 - Introduction and Mathematical Concepts - Problems - Page 21: 27


$1199$ m at $25.7^{\circ}$ from east

Work Step by Step

The question asks for the distance between the turning point and the camp. We can find the leg of the triangle by subtracting 1430 from 1950. This gives 520. The second leg of the triangle is equal to 1080. To find the distance we can use the pythagorean theorem. $x^{2}=1080^{2}+520^{2}$ $x=1199$ m To find the angle we can use tangent in the triangle. $tan\theta=\frac{1080}{520}$ $\theta=64.3^{\circ}$ We subtract this angle from 90 degrees to find the angle from east. $90^{\circ}-64.3^{\circ}=25.7^{\circ}$
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