Physics (10th Edition)

Published by Wiley

Chapter 1 - Introduction and Mathematical Concepts - Problems - Page 21: 18

Answer

$29.6^{\circ}, 51.2^{\circ}, 99.2^{\circ}$

Work Step by Step

$\gamma = cos^{-1}(\frac{(150)^{2}+(190)^{2}-(95)^{2}}{(2)(150)(190)}) \approx 29.6^{\circ}$ $\alpha = cos^{-1}(\frac{(95)^{2}+(190)^{2}-(150)^{2}}{(2)(95)(190)}) \approx 51.2^{\circ}$ $\beta$ = 180 - (51.2) - (29.6) = 99.2$^{\circ}$

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