## Physics (10th Edition)

∠ BAC = 180 - 51 - 77 = 52$^{\circ}$ Using cosine rule: $cos(52^{\circ})=\frac{62^{2}+x^{2}-95^{2}}{2(62)(x)}$ 0.61566 = $\frac{x^{2}-5181}{124x}$ 76$x$ = $x^{2}$ - 5181 $x^{2}$ - 76$x$ - 5181 = 0 Using quadratic equation: $x = \frac{-(-76)±\sqrt ((-76)^{2}=4(1)(-5181))}{2(1)}$ $x\approx 120$ m since $x\gt0$