Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 1 - Introduction and Mathematical Concepts - Problems - Page 21: 22

Answer

$32.0^{\circ}$

Work Step by Step

$x = 8cos(41^{\circ})$ $y = \frac{0.75}{cos(\theta)}$ $cos(\theta)=\frac{x}{8-y} = \frac{8cos(41^{\circ})}{8-\frac{0.75}{cos(\theta)}} $ $(cos(\theta))(8-\frac{0.75}{cos(\theta)}) = 8cos(41^{\circ})$ $8cos(\theta) - 0.75 = 8cos(41^{\circ})$ $8(cos(\theta) - cos(41^{\circ})) = 0.75 $ $cos(\theta) - cos(41^{\circ}) = 0.09375 $ $\theta = cos^{-1}(0.09375+ cos(41^{\circ})) \approx 32.0^{\circ} $
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