## Physics (10th Edition)

$32.0^{\circ}$
$x = 8cos(41^{\circ})$ $y = \frac{0.75}{cos(\theta)}$ $cos(\theta)=\frac{x}{8-y} = \frac{8cos(41^{\circ})}{8-\frac{0.75}{cos(\theta)}}$ $(cos(\theta))(8-\frac{0.75}{cos(\theta)}) = 8cos(41^{\circ})$ $8cos(\theta) - 0.75 = 8cos(41^{\circ})$ $8(cos(\theta) - cos(41^{\circ})) = 0.75$ $cos(\theta) - cos(41^{\circ}) = 0.09375$ $\theta = cos^{-1}(0.09375+ cos(41^{\circ})) \approx 32.0^{\circ}$