Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 1 - Introduction and Mathematical Concepts - Problems: 20

Answer

2.8 mi

Work Step by Step

a) distance $= \sqrt (6.38\times 10^{6} +1.6)^{2} - (6.38\times 10^{6})^{2}$ $\approx$ 4518.4071 m $\approx$ 4518.4 m b) distance = $4518.4071\; m \times \frac{1\; mi}{1609\; m} $ $\approx$ 2.8 mi
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