## Physics (10th Edition)

a) distance $= \sqrt (6.38\times 10^{6} +1.6)^{2} - (6.38\times 10^{6})^{2}$ $\approx$ 4518.4071 m $\approx$ 4518.4 m b) distance = $4518.4071\; m \times \frac{1\; mi}{1609\; m}$ $\approx$ 2.8 mi