## Physics (10th Edition)

Published by Wiley

# Chapter 1 - Introduction and Mathematical Concepts - Problems - Page 20: 7

2.0 magnums

#### Work Step by Step

1 jeroboam = 0.792 US gallons = $0.792\; US\; gallons \times \frac{3.785\times 10^{-3}\; m^{3}}{1\; US\; gallon} \times \frac{1\; L}{10^{-3}\; m^{3}}$ $\approx$ 3.00 L Number of magnums in a jeroboam = 3.00 L $\div$ 1.5 L = 2.0 magnums

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