Answer
$0.528\; km$
Work Step by Step
Let $x$ = distance from base of arch
$tan(20^{\circ}) = \frac{192}{x} $
$x = \frac{192}{tan(20^{\circ})} $
$x$
$ \approx 527.52\; m$
$= 527.52\; m \times \frac{1\; km}{1000\; m}$
$= 0.528\; km$
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 1 - Introduction and Mathematical Concepts - Problems - Page 20: 12
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
