Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 1 - Introduction and Mathematical Concepts - Problems: 13

Answer

80.1 km, 25.9$^{\circ}$ south of west

Work Step by Step

Let $x$ = length of highway $x = \sqrt (72.0^{2} + 35.0^{2}) = \sqrt 6409 \approx 80.1\; km $ $tan(\theta) = \frac{35.0}{72.0}$ $\theta\approx25.9^{\circ}$ south of west (or north of east)
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