Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 1 - Introduction and Mathematical Concepts - Problems: 5

Answer

0.75 $m^{2}/s $

Work Step by Step

d = $\frac{a^{3}}{cb^{2}}$ = $\frac{a^{3}}{c} \times \frac{1}{b^{2}}$ = $\frac{(9.7m)^{3}}{69\; m/s} \times \frac{1}{(4.2s)^{2}}$ = $912.673 m^{3} \times \frac{1\; s}{69\; m} \times \frac{1}{17.64\; s^{2}} $ $\approx$ 0.75 $m^{2}/s $
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