Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 1 - Introduction and Mathematical Concepts - Problems: 6

Answer

[T]$^{-3}$

Work Step by Step

$v = \frac{1}{3}zxt^{2}$ $z = \frac{3v}{xt^{2}} $ = $3v \times \frac{1}{x} \times \frac{1}{t^{2}} $ Dimensions of z = $ \frac{[L]}{[T]} \times \frac{1}{[L]} \times \frac{1}{[T]^{2}} $ = $\frac{1}{[T]^{3}}$ = [T]$^{-3}$
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