## Physics (10th Edition)

[T]$^{-3}$
$v = \frac{1}{3}zxt^{2}$ $z = \frac{3v}{xt^{2}}$ = $3v \times \frac{1}{x} \times \frac{1}{t^{2}}$ Dimensions of z = $\frac{[L]}{[T]} \times \frac{1}{[L]} \times \frac{1}{[T]^{2}}$ = $\frac{1}{[T]^{3}}$ = [T]$^{-3}$