Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems - Page 173: 36

Answer

The work done by the force is $~~25.0~J$

Work Step by Step

To find the work done, we can calculate the area under the force versus position curve. This area can be divided into three parts, including a rectangle (0 to 2 m), a triangle, (2 m to 4 m), and a triangle (6 m to 8 m). We can find each area separately: $A_1 = (10.0~N)(2~m) = 20.0~J$ $A_2 = \frac{1}{2}(10.0~N)(2~m) = 10.0~J$ $A_3 = \frac{1}{2}(-5.0~N)(2~m) = -5.0~J$ We can find the work done by the force: $W = 20.0~J+10.0~J-5.0~J = 25.0~J$ The work done by the force is $~~25.0~J$.
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