Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems - Page 173: 34

Answer

The work done on the brick by the force is $~~800~J$

Work Step by Step

We can write an expression for the acceleration at $x$: $a = 2.5~x$ We can write an expression for $F$: $F = ma$ $F = 2.5~mx$ $F = 25x$ We can find the work done on the brick by the force: $W = \int^{8.0}_{0}25x~dx$ $W = 12.5x^2~\Big\vert^{8.0}_{0}$ $W = (12.5)(8.0)^2-(12.5)(0)^2$ $W = 800~J$ The work done on the brick by the force is $~~800~J$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.