Answer
Tension in the cable $ =24.3$ $kN$
Work Step by Step
Let $W$ be the weight (Given as $27.8kN$)
So, $W = mg = m\times 9.8 m/s^{2}$
This means that mass $ =27800 N \div 9.8 = 2836.7$ $kg$
Acceleration given in this case $= - ( 1.22$ $m/s^{2} )$
So, total Tension in cable is:
$W+ma = 27800N+ [2836.7 \times (-1.22) ]$
$W+ma = (27800-3860.7) N$
$W+ma= 24.3$ $kN$
