Answer
$$T=73 \mathrm{\ N}$$
Work Step by Step
it's easy for us to know that with the uphill acceleration of 0.10 $\mathrm{m} / \mathrm{s}^{2}$ , Newton's second law (applied to the $x$ axis) yields
$$
T- \left[(m)\times (g)\times (\sin \theta) \right]=(m) \times(a) \Rightarrow
$$
$$T-(50 \mathrm{kg})\left(9.8 \mathrm{m} / \mathrm{s}^{2}\right) \sin 8.0^{\circ}=(50 \mathrm{kg})\left(0.10 \mathrm{m} / \mathrm{s}^{2}\right)$$
which leads to $T=73 \mathrm{\ N}$ .
