Answer
$F=1.23N$
Work Step by Step
The force that link 2 exerts on link 1 can be calculated by adding the weight of link 1 to the force required to accelerate the link at $2.50m/s^2$,
$F=F_g+ma=m(g+a)=(0.100kg)[(9.8m/s^2)+(2.50m/s^2)]=1.23N$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 5 - Force and Motion-I - Problems - Page 119: 43a
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