Answer
$F3 = (1.7i + 3.1j) N$
Work Step by Step
With the information provided, we find the x and y components of F1 and F2.
$F1_{x} = -6 cos (30^{\circ})$
$F1_{y} = 6 sin (30^{\circ})$
$F2_{x} = 7 cos (30^{\circ})$
$F2_{y} = -7 sin (30^{\circ})$
For the lemon to stay stationary, Fnet = 0.
Therefore:
F1 + F2 + F3 = 0
F3 = -(F1 + F2)
This means:
$F3_{x} = -(-5.2 + 3.5)i = 1.7i$
$F3_{y} = -(3 - 6.1)j = 3.1j$
$F3 = (1.7i + 3.1j) N$
