Answer
$201^{\circ}$
Work Step by Step
$\theta =tan^{-1} (\frac{F_x}{F_y})$
$\theta =tan^{-1} (\frac{-2400}{-6800})$
$\theta =21^{\circ}$ or $201^{\circ}$
The force is in the third quadrant so the angle is $201^{\circ}$.
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 5 - Force and Motion-I - Problems - Page 119: 42b
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