Answer
$X_{\max }=64.28m$
Work Step by Step
The canon and the net are located on the same height. This means that the object will travel maximum horizontal distance to hit the net.
So, let us write the maximum horizontal distance equation:
$X_{\max }=\dfrac {2v^{2}_{0}\sin \theta _{0}\cos \theta _{0}}{g}$
where $v_{0}=25.6\dfrac {m}{s};\theta _{0}=53^{0};g=9.8\dfrac {m}{s^{2}}$
Substituting these values in the formula above, we get
$X_{\max }=64.28m$
