Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 4 - Motion in Two and Three Dimensions - Problems: 42c

Answer

$X_{\max }=64.28m$

Work Step by Step

The canon and the net are located on the same height. This means that the object will travel maximum horizontal distance to hit the net. So, let us write the maximum horizontal distance equation: $X_{\max }=\dfrac {2v^{2}_{0}\sin \theta _{0}\cos \theta _{0}}{g}$ where $v_{0}=25.6\dfrac {m}{s};\theta _{0}=53^{0};g=9.8\dfrac {m}{s^{2}}$ Substituting these values in the formula above, we get $X_{\max }=64.28m$
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