Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 4 - Motion in Two and Three Dimensions - Problems - Page 86: 34b

Answer

24.49m/s

Work Step by Step

$v $ (initial velocity)$= 31m/s$ $ v_{x} = 19m/s$ Formula for horizontal velocity: $v^{2} = {v_{x}}^{2} + {v_{y}}^{2}$ Make ${v_{y}}$ the subject of the formula: $ {v_{y}}^{2} = v^{2} - {v_{x}}^{2}$ $ {v_{y}} = \sqrt {v^{2} - {v_{x}}^{2}}$ Substitute the values into the equation: $ {v_{y}} = \sqrt {31m/s^{2} - {19m/s}^{2}}$ $ {v_{y}} = 24.49$
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