Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 4 - Motion in Two and Three Dimensions - Problems - Page 86: 38a

Answer

$x= 95m$

Work Step by Step

$t=5s$ At t =0, the vertical component, $v_{y}$, is equal to zero so the velocity at this point is equal to $v_{x}$ $v_{x} = 19m/s$ Formula for horizontal distance: $x=v_{x} \times t$ $x=19m/s \times 5s$ $x= 95m$
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