Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 4 - Motion in Two and Three Dimensions - Problems: 37c

Answer

$2.86m$

Work Step by Step

First, lets calculate when the diver strikes the water. Lets assume the height of water is 0m and diver started 10 m above the water (assume it is $H_{0}$). So the time passed till the diver strikes the water will be $H_{0}-\dfrac {gt^{2}}{2}=0\Rightarrow 10m-\dfrac {9,8\dfrac {m}{s^{2}}t^{2}}{2}=0\Rightarrow t\approx 1.43s$. Using this time, we can calculate horizontal distance easily because horizontal velocity of diver doesn't change. So the horizontal distance will be $L=v_{0}t\approx 2.86m$.
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