Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 28 - Magnetic Fields - Problems - Page 832: 58

Answer

$i=2.08\times 10^9A$

Work Step by Step

We know that: $\mu=i A$ $\mu=i \pi r^2$ We re-arrange the formula: $i=\frac{\mu}{\pi r^2}$ We plug in the known values to obtain: $i=\frac{8\times 10^{22}}{3.1416\times (3500\times 10^3)^2}$ $i=2.08\times 10^9A$
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