Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 28 - Magnetic Fields - Problems - Page 832: 56a

Answer

$\mu=0.184Am^2$

Work Step by Step

We can find the magnitude of the magnetic dipole moment as: $\mu=IA$ where $I$ is the current and $A$ is the area. This can be written as: $\mu=I\pi r^2$ We plug in the known values in the formula to obtain: $\mu=2.60\times 3.1416\times (0.15)^2$ $\mu=0.184Am^2$
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