Answer
$T_{maz}=0.0805N.m$
Work Step by Step
The maximum torque is
$T_{max}=\mu B$
We plug in the values of $\mu$ and $B$ to obtain:
$T_{maz}=2.30\times 35\times 10^{-3}$
$T_{maz}=0.0805N.m$
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