Answer
$T = 0i + (-4.33*10^{-3} N*m)j + 0k$
Work Step by Step
The angle given is $30^{\circ}$, use this to calculate the angle between the normal vector and the magnetic field.
$\theta = 90^{\circ} - 30^{\circ}$
Torque
$T = NiABsin\theta$
$T = (20)*(0.10)*(0.10*0.05)*(0.5)*sin\theta$
$T = 4.33*10^{-3} N*m$
Torque is in the negative $j$ direction because torque is pointed in the same axis as the one the object is rotating in.
$T = 0i + (-4.33*10^{-3} N*m)j + 0k$
