Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 28 - Magnetic Fields - Problems - Page 832: 55a

Answer

$2.86\,Am^{2}$

Work Step by Step

Recall that when the number of turns N=1, $\mu=iA$. $\mu_{net}=\mu_{1}+\mu_{2}=iA_{1}+iA_{2}=i(\pi r_{1}^{2}+\pi r_{2}^{2})$ $=7.00\,A\times\pi((20.0\times10^{-2}\,m)^{2}+(30.0\times10^{-2}m)^{2})=2.86\,Am^{2}$
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