Answer
$J = 2.4\times 10^{-5}~A/m^2$
Work Step by Step
We can find the current density:
$J = \frac{current}{area}$
$J = \frac{i}{\pi~r^2}$
$J = \frac{1.2\times 10^{-10}~A}{(\pi)~(1.25\times 10^{-3}~m)^2}$
$J = 2.4\times 10^{-5}~A/m^2$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 26 - Current and Resistance - Problems - Page 766: 8a
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