Answer
$\rho = 8.2\times 10^{-8}~\Omega\cdot m$
Work Step by Step
We can find the resistivity of the wire:
$J = \frac{i}{A}$
$J = \frac{V}{R~A}$
$J = \frac{V}{(\rho~L/A)~A}$
$J = \frac{V}{\rho~L}$
$\rho = \frac{V}{J~L}$
$\rho = \frac{115~V}{(1.4\times 10^8~A/m^2)(10~m)}$
$\rho = 8.2\times 10^{-8}~\Omega\cdot m$
