Answer
1.53 kA
Work Step by Step
Given: $V= 23.0 V, R= 15.0 m\Omega$
Recall: $I=\frac{V}{R}$
Substitute the values of V and R:
$I= \frac{23.0 V}{15.0\times10^{-3}\Omega}=1.53\times10^{3}A= 1.53 kA$
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