Answer
$r_2=1.23 mm$
Work Step by Step
We can derive the equation for $r_2$, as we derived for $r_1$ in 24(a)
Thus:
$r_2=r_3\sqrt\frac{E_3}{E_2}$
We plug in the known values to obtain:
$r_2=2\sqrt\frac{1.5}{4}$
$r_2=1.23 mm$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 26 - Current and Resistance - Problems - Page 766: 24b
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