Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 26 - Current and Resistance - Problems - Page 766: 12b

Answer

$i=8.33\times10^7 A$

Work Step by Step

We know that $i=JA$ $i=J\pi{R_E^2}$ We plug in the known values to obtain: $i=6.54\times10^{-7}\times3.1416\times(6.37\times10^6)^2$ $i=8.33\times10^7 A$
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