Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 25 - Capacitance - Problems - Page 739: 4b

Answer

$1.9\times 10^{-2}\ m^2$

Work Step by Step

The formula for the capacitance with plate area A is given by; $C =\frac{ A \epsilon_o}{b-a}$ Rearranging the above formula for A, Area $A = \frac{C(b-a)}{\epsilon_o}$ Now substitute corresponding values i,e $C = 84.5 pF , a = 0.038 m , b=0.04 m$ $A = \frac{(84.5\times 10^{-12} F)(0.04 m-0.038 m)}{(8.85\times 10^{-12}\ c^2/N.m^2)}$ $A = 1.9\times 10^{-2} m^2$
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