Answer
$3\times 10^{-3}\ C$
Work Step by Step
Given,
The value of capacitance $C = 25 \mu F$
The potential difference $V =120 V$
The charge(q) stored is given by formula
$q = CV$
is;
$q=(25\times 10^{-6} F )(120 V)$
$q = 3\times 10^{-3} C$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 25 - Capacitance - Problems - Page 739: 2
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