Answer
$ 17.3\ nC$
Work Step by Step
Charge $(q)$ stored in the plates of the capacitor is given by;
$q = CV$
$q=(144\times 10^{-12}\ F)(120\ V)$
$q=17.3\times 10^{-9} c$
$q = 17.3\ nc$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 25 - Capacitance - Problems - Page 739: 3b
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