Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 25 - Capacitance - Problems - Page 739: 4a

Answer

$84.5\ pF$

Work Step by Step

Capacitance of spherical capacitor is given by, $C = 4\pi \epsilon_o \frac{ab}{b-a}$ From the given data, we know that, radii of capacitors $a = 38 mm = 0.038 m$ and $b= 40 mm = 0.04 m$ Substituting these values in the formula and solving: $C = 4\pi \epsilon_o \frac{ab}{b-a}$ $C =4\pi(8.85\times10^{-12}\ c^2/Nm^2)\ (\frac{(0.038 m)(0.04 m)}{(0.04m-0.038m)}) $ $C=84.5\times 10^{-12} F$ $C= 84.5\ pF$
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