# Chapter 25 - Capacitance - Problems - Page 739: 1a

$C=3.5pF$

#### Work Step by Step

We can find the the capacitance as: $C=\frac{q}{V}$ We plug in the known values to obtain: $C=\frac{70\times 10^{-12}}{20}$ $C=3.5\times 10^{-12}=3.5pF$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.