Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 25 - Capacitance - Problems: 1a

Answer

$C=3.5pF$

Work Step by Step

We can find the the capacitance as: $C=\frac{q}{V}$ We plug in the known values to obtain: $C=\frac{70\times 10^{-12}}{20}$ $C=3.5\times 10^{-12}=3.5pF$
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