Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 22 - Electric Fields - Problems - Page 657: 62a

Answer

$a=2.46\times10^{17}\frac{m}{s^2}$

Work Step by Step

As $F=qE$ and $F=ma$ so $ma=qE$ Rearranging the above equation, $a=\frac{qE}{m}$ Putting the values into the formula and solving: $a=\frac{(1.6\times10^{-19})(1.4\times10^6)}{9.11\times10^{-31}}$ $a=2.46\times10^{17}\frac{m}{s^2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.