Answer
$p = 9.30\times 10^{-15}~C\cdot m$
Work Step by Step
We can find the magnitude of the electric dipole moment:
$p = qd$
$p = (1.50\times 10^{-9}~C)(6.20\times 10^{-6}~m)$
$p = 9.30\times 10^{-15}~C\cdot m$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 22 - Electric Fields - Problems - Page 657: 57a
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