Answer
$E=1.0 \times 10^3 \mathrm{~N} / \mathrm{C} .$
Work Step by Step
We use $\Delta x=\frac{1}{2} a t^2$ and $E=F / e=m a / e$ :
$
E=\frac{m a}{e}=\frac{2 \Delta x m}{e t^2}=\frac{2\left\{2.0 \times 10^{-2} \mathrm{~m} \mid\left[9.11 \times 10^{-31} \mathrm{~kg}\right\}\right.}{\left(1.60 \times 10^{-19} \mathrm{C} \mid\left[1.5 \times 10^{-8} \mathrm{~s}\right)^2\right.}\\=1.0 \times 10^3 \mathrm{~N} / \mathrm{C} .
$
