Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 22 - Electric Fields - Problems - Page 657: 57b

Answer

The difference between the potential energies is $~~\Delta U = 2.05\times 10^{-11}~J$

Work Step by Step

We can find the magnitude of the electric dipole moment: $p = qd$ $p = (1.50\times 10^{-9}~C)(6.20\times 10^{-6}~m)$ $p = 9.30\times 10^{-15}~C\cdot m$ When the dipole orientation is parallel: $U = -p~E$ When the dipole orientation is antiparallel: $U = p~E$ We can find the difference between the potential energies: $\Delta U = p~E-(-p~E)$ $\Delta U = 2p~E$ $\Delta U = (2)(9.30\times 10^{-15}~C\cdot m)(1100~N/C)$ $\Delta U = 2.05\times 10^{-11}~J$ The difference between the potential energies is $~~\Delta U = 2.05\times 10^{-11}~J$
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