Answer
$q=1.11\times10^{-10}C=1.11\times10^{-4}\mu C$
Work Step by Step
Electric field strength is given as:
$E=\frac{1}{4\pi\epsilon_\circ}.\frac{q}{r^2}$
Here $\frac{1}{4\pi\epsilon_\circ}=K=8.99\times10^9\frac{N.m^2}{C^2}$
Therefore,
$E=K.\frac{q}{r^2}$
$q=\frac{E.r^2}{K}$
Putting the values in the above formula and solving:
$q=\frac{(1.0).(1.0)^2}{8.99\times10^9}$
$q=1.11\times10^{-10}C=1.11\times10^{-4}\mu C$
