Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 22 - Electric Fields - Problems - Page 653: 5

Answer

$q=56pC$

Work Step by Step

As we know that $E=\frac{q}{4\pi{\epsilon_{\circ}}r^2}$ or $q=4\pi{\epsilon_{\circ}}r^2E$ Putting the values $q=4(3.14)(8.854\times10^{-12})(50\times10^{-2})^2(2.00)$ $q=5.56\times10^{-11}C$ $q=55.6\times10^{-1}\times10^{-11}C$ $q=55.6\times10^{-12}C$ or $q=56pC$
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