Answer
$F = 6.4\times 10^{-18}~N$
Work Step by Step
We can find the magnitude of the force on a proton due to the electric field at A:
$F = q~E$
$F = (1.6\times 10^{-19}~C)(40~N/C)$
$F = 6.4\times 10^{-18}~N$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 22 - Electric Fields - Problems - Page 653: 2a
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