Answer
The graph is shown in the picture.
Work Step by Step
We have the information of the distance $d = 1100m$, first-half acceleration $a1 = +1.2m/s^{2}$, and second-half acceleration $a2 = -1.2m/s^{2}$. To draw a graph without using a computer, we have to know the properties of the function.
Let's start with the easiest one, which is the acceleration graph.
The $a$ vs $t$ graph is a horizontal line in the time interval when the acceleration occurs.
For $a1$, the time interval is from $t0 = 0$ to $t1 = \sqrt {d/a1} = 30.3s$.
For $a2$, the time interval is from $t1 = 30.3s$ to $t2 = 2\times t1 = 60.6s$.
The $v$ vs $t$ graph is a straight line with a positive gradient, which is $a1$, from $t0$ to $t1$;
and a straight line with a negative gradient, which is $a2$, from $t1$ to $t2$.
The $x$ vs $t$ graph is a quadratic curve:
the first part from $t0$ to $t1$ is part of an opens-up quadratic function because it starts slowly and grows faster as time goes on (it's accelerating).
the second part from $t1$ to $t2$ is part of an open-down quadratic function because it starts fast and slows down as time goes on (it's decelerating).
