Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems - Page 37: 82

Answer

$39 \frac{m}{s}$

Work Step by Step

Integrating from $t = -2$ to $t = 6$, we have an area that is a right triangle with base $6$ and height $12$, so an area of $48$ and a smaller one to be subtracted with base $2$ and height $4$, so area $4$. Adding this to the initial speed of $7$, we have a final velocity of $39 \frac{m}{s}$
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