Answer
The spot is moving right just before coming to rest.
Work Step by Step
$x = 9.00~t- 0.750~t^3$
$v = 9.00-2.25~t^2$
At $t=2.00~s$, the spot is at rest.
On the interval $0\leq t \lt 2$, then $v \gt 0$
Therefore, the spot is moving right (in the positive direction) just before coming to rest.
