Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems - Page 37: 72b

Answer

$h\approx12.5m$

Work Step by Step

We know the following equation: $h=v_{0}t+\frac{1}{2}gt^{2}$ We plug in the known values to obtain: $h=(15.68m/s)(1.60s)+\frac{1}{2}(-9.8m/s^{2})(1.60s)^{2}$ $h\approx12.5m$
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