Answer
$v\approx19.0m/s$
Work Step by Step
We know the following equation:
$v^{2}_{f}=v^{2}_{0}+2ax$
This simplifies to:
$v_{f}=\sqrt {v^{2}_{0}+2ax}$
We plug in the known values to obtain:
$v_{f}=\sqrt {(0m/s)^{2}+2(2.2m/s^{2})(82.0m)}$
$v_{f}\approx19.0m/s$
Another way to solve:
$v=at$
$v=(2.2m/s^{2})(8.64s)$
$v\approx19.0m/s$
