Answer
$a=5m/s^{2}$
Work Step by Step
We know the following equation:
$v^{2}_{f}=v^{2}_{0}+2ax$
$v^{2}_{f}-v^{2}_{0}=2ax$
We plug in the known values to obtain:
$a=\frac{v^{2}_{f}-v^{2}_{0}}{2x}=\frac{(50m/s)^{2}-(30m/s)^{2}}{2(160m)}=5m/s^{2}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 2 - Motion Along a Straight Line - Problems - Page 37: 80a
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